overflow group

[zgti]

Hi,

Customer wants to have this:
Three calls in queue. Next call comes in. First position in queue has to go to overflow group.
Then second call will be first in queue and third will be second in queue.
Next call comes in. First call has to go to overflow group, and so on and on and on....

So basically, first in, first out, but then to overflow group as long as original group has no free agents.

Is this possible?

Regards, Peter

[zgti]

Problem solved!

[lebon]

Hi

I am interested in your script, I have a client that asks me the same thing a can

[zgti]

Hi,

I have created this in a logic (Calls in que).:

q(IN)[].callsInQueue >= 2
&&
c.positionInQueue == 1
&&
c.waitThisQueue > 15
||
c."Bestaande oproep" == "ja"

So, when there are two calls in the queue, and a third call enters the queue, after 15 seconds, the first call goes to the overflow group.
The "Bestaande oproep" is a calltag, in English "Existing call". It makes the call stay in the upper part of the callflow.


Regards, Peter

[lebon]

veru good

thank